w3.css

목록 정렬

JavaScript를 사용하여 HTML 목록을 정렬하는 방법을 알아보자.

정렬 함수 생성

1단계) HTML 추가

<ul id="id01">
  <li>Oslo</li>
  <li>Stockholm</li>
  <li>Helsinki</li>
  <li>Berlin</li>
  <li>Rome</li>
  <li>Madrid</li>
</ul>

<script>
function sortList() {
  var list, i, switching, b, shouldSwitch;
  list = document.getElementById("id01");
  switching = true;
  /* Make a loop that will continue until
  no switching has been done: */
  while (switching) {
    // Start by saying: no switching is done:
    switching = false;
    b = list.getElementsByTagName("LI");
    // Loop through all list items:
    for (i = 0; i < (b.length - 1); i++) {
      // Start by saying there should be no switching:
      shouldSwitch = false;
      /* Check if the next item should
      switch place with the current item: */
      if (b[i].innerHTML.toLowerCase() > b[i + 1].innerHTML.toLowerCase()) {
        /* If next item is alphabetically lower than current item,
        mark as a switch and break the loop: */
        shouldSwitch = true;
        break;
      }
    }
    if (shouldSwitch) {
      /* If a switch has been marked, make the switch
      and mark the switch as done: */
      b[i].parentNode.insertBefore(b[i + 1], b[i]);
      switching = true;
    }
  }
}
</script>

오름차순 및 내림차순 정렬

버튼을 처음 클릭하면 정렬 방향이 오름차순(A~Z)으로 설정된다.

다시 클릭하면 정렬 방향이 내림차순(Z에서 A)으로 변경된다.

예제

<ul id="id01">
  <li>Oslo</li>
  <li>Stockholm</li>
  <li>Helsinki</li>
  <li>Berlin</li>
  <li>Rome</li>
  <li>Madrid</li>
</ul>

<script>
function sortListDir() {
  var list, i, switching, b, shouldSwitch, dir, switchcount = 0;
  list = document.getElementById("id01");
  switching = true;
  // Set the sorting direction to ascending:
  dir = "asc";
  // Make a loop that will continue until no switching has been done:
  while (switching) {
    // Start by saying: no switching is done:
    switching = false;
    b = list.getElementsByTagName("LI");
    // Loop through all list-items:
    for (i = 0; i < (b.length - 1); i++) {
      // Start by saying there should be no switching:
      shouldSwitch = false;
      /* Check if the next item should switch place with the current item,
      based on the sorting direction (asc or desc): */
      if (dir == "asc") {
        if (b[i].innerHTML.toLowerCase() > b[i + 1].innerHTML.toLowerCase()) {
          /* If next item is alphabetically lower than current item,
          mark as a switch and break the loop: */
          shouldSwitch = true;
          break;
        }
      } else if (dir == "desc") {
        if (b[i].innerHTML.toLowerCase() < b[i + 1].innerHTML.toLowerCase()) {
          /* If next item is alphabetically higher than current item,
          mark as a switch and break the loop: */
          shouldSwitch= true;
          break;
        }
      }
    }
    if (shouldSwitch) {
      /* If a switch has been marked, make the switch
      and mark that a switch has been done: */
      b[i].parentNode.insertBefore(b[i + 1], b[i]);
      switching = true;
      // Each time a switch is done, increase switchcount by 1:
      switchcount ++;
    } else {
      /* If no switching has been done AND the direction is "asc",
      set the direction to "desc" and run the while loop again. */
      if (switchcount == 0 && dir == "asc") {
        dir = "desc";
        switching = true;
      }
    }
  }
}
</script>

목록을 숫자순으로 정렬

if (Number(b[i].innerHTML) > Number(b[i + 1].innerHTML)) {
  shouldSwitch =  true;
  break;
}

Mingg`s Diary

밍구

공부 목적 블로그

https://maz.kr

모든 포스트 보기